AP 5th Maths Addition and Subtraction Workbook Solutions and Answers

AP 5th Maths Addition and Subtraction Workbook Solutions and Answer. APSCERT 5th Class Maths Unit 2 Addition and Subtraction Workbook Solutions and Answers for All Exercises and Worksheets page wise. For All 5th Solutions Click Here
AP 5th Maths Addition and Subtraction Workbook Solutions and Answers

📗 Class 5 Maths Workbook — Unit 2: Addition and Subtraction — Answer Key

Worksheet - 1 (Page 21): Recall Addition

I. a) 1,759 + 6,950 = 8,709

I. b) 7,850 + 1,858 = 9,708

I. c) 5,709 + 5,587 = 11,296

II. a) 8,047 + 6,113 = 14,160

II. b) 1,235 + 6,712 = 7,947

III. Predecessor of 1420 = 1,419; Successor of 1420 = 1,421. Sum = 1,419 + 1,421 = 2,840

IV. Siva's money = 6,589 + 1,508 = 8,097. Total with Rani and Siva = 6,589 + 8,097 = ₹14,686

Worksheet - 2 (Page 22–23): Addition

I. a) 76,921 + 58,147 = 1,35,068

I. b) 42,543 + 79,153 = 1,21,696

I. c) 22,222 + 99,999 = 1,22,221

II. a) 61,800 + 50,027 — Estimation ≈ 62,000 + 50,000 = 1,12,000; Exact sum = 1,11,827

II. b) 91,447 + 37,466 — Estimation ≈ 91,000 + 37,000 = 1,28,000; Exact sum = 1,28,913

Were the estimations close? Yes, both estimations were very close to the exact sums, since rounding each number to the nearest thousand keeps the estimate within a small margin of the actual total.

III. a) Total sacks = 78,449 + 55,774 + 48,557 = 1,82,780 sacks

III. b) Mathematical statement: 78,449 + 55,774 + 48,557 = 1,82,780

IV. Total amount Sumathi has to pay = 8,699 (chair) + 3,650 (table) + 1,550 (white board) = ₹13,899

Worksheet - 3 (Page 24): Subtractions 5th Maths Addition and Subtraction

I. 58,397 − 45,265 = 13,132

I. 52,131 − 33,267 = 18,864

I. 11,111 − 9,999 = 1,112

II. a) 16,225 − 6,025 = 10,200

II. b) 78,365 − 19,988 = 58,377

III. Ajay's money = 9,679 − 1,406 = ₹8,273

IV. Checking each pair (number − reversed number):
A) 8534 − 4358 = 4176 (no)   B) 7641 − 1467 = 6174 ✔   C) 9315 − 5139 = 4176 (no)   D) 6422 − 2246 = 4176 (no)
Answer: Option B) 7641 and 1467

Worksheet - 4 (Page 25–26): Addition and Subtraction

Table: TV ₹35,000 | Fridge ₹46,000 | Cell phone ₹24,000 | Cooler ₹15,000 | Fan ₹1,500 | Study light ₹800

1. With ₹50,000, you can buy: (a) TV (₹35,000) and (b) Cooler (₹15,000) → Total = ₹50,000 (any combination totalling ≤ ₹50,000 is acceptable)

II. a) TV + Fridge = 35,000 + 46,000 = ₹81,000

II. b) Cell phone − Cooler = 24,000 − 15,000 = ₹9,000

III. Highest price = ₹46,000 (Fridge); Lowest price = ₹800 (Study light)

III. i) Highest + Lowest = 46,000 + 800 = ₹46,800

III. ii) Highest − Lowest = 46,000 − 800 = ₹45,200

IV. Akash's total = Cell phone + Fan + Study light = 24,000 + 1,500 + 800 = 26,300; After ₹2,500 concession = 26,300 − 2,500 = ₹23,800

Worksheet - 5 (Page 27): Addition and Subtraction

I. Subtraction facts for given additions:

AdditionSubtraction Facts
3,482 + 1,237 = 4,7194,719 − 1,237 = 3,482  and  4,719 − 3,482 = 1,237
5,806 + 3,784 = 9,5909,590 − 3,784 = 5,806  and  9,590 − 5,806 = 3,784
3,816 + 4,785 = 8,6018,601 − 4,785 = 3,816  and  8,601 − 3,816 = 4,785

II. a) 56,384 + 48,364 − 38,486 → Add: 56,384+48,364=1,04,748; Subtract: 1,04,748−38,486 = 66,262

II. b) 43,768 + 4,325 − 5,238 → Add: 43,768+4,325=48,093; Subtract: 48,093−5,238 = 42,855

III. Sum of 54,656 and 13,426 = 68,082; Amount to be added to get 71,181 = 71,181 − 68,082 = 3,099

IV. Total earnings = 37,645 + 25,367 = 63,012; Savings = 63,012 − 38,600 = ₹24,412

Worksheet - 6 (Page 28): Addition and Subtraction (Properties) APTEACHERS.IN

I. a) 78,360 + 38,465 = 38,465 + 78,360

I. b) 52,014 + 72,541 = 72,541 + 52,014 (Note: this shows 52,014 + 72,541 equals 72,541 + 52,014)

I. c) 21,543 + 0 = 21,543

I. d) 67,380 + 0 = 0 + 67,380

II. (i) If you add 0 to 54,321, the sum is 54,321 → True

II. (ii) The sum of 1,250 and 8,750 is different from the sum of 8,750 and 1,250 → False (both sums are equal to 10,000 — order doesn't change the sum)

II. (iii) 12,450 + 0 = 12,451 → False (correct answer is 12,450)

II. (iv) The sum of 10,000 and 20,000 is exactly the same as the sum of 20,000 and 10,000 → True

III. a) 34,685 + 26,366 = 61,051; and 26,366 + 34,685 = 61,051. Conclusion: Both sums are equal — changing the order of the addends does not change the total (Commutative Property of Addition).

IV. 1) Number to be added to 9,325 to get 9,325 again = 0 → Option B) 0

Worksheet - 7 (Page 29): Estimation on Sum and Difference 5th Maths Addition and Subtraction

I. a) 58,397 + 45,965 ≈ 58,000 + 46,000 = 1,04,000

I. b) 25,098 − 14,992 ≈ 25,000 − 15,000 = 10,000

II. Match with estimations:

(i) 36,541 + 12,112 ≈ 37,000+12,000 = 49,000 → D) 49000

(ii) 25,631 + 56,121 ≈ 26,000+56,000 = 82,000 → C) 82000

(iii) 96,521 − 43,164 ≈ 97,000−43,000 = 53,000 (actual 53,357) → B) 53000

(iv) 8,925 − 2,222 ≈ 9,000−2,000 = 7,000 (actual 6,703) → A) 7000

III. Estimated sum (nearest thousand) of two numbers = 90,000. One number is 46,780 (rounds to 47,000). So the second number should round to 90,000 − 47,000 = 43,000. The second number could be any number close to 43,000 (for example, 43,150).

IV. Rani collected ₹3,578, Meena collected ₹2,456. Actual difference = 3,578 − 2,456 = 1,122, which is closest to Option C) ₹1,000

Worksheet - 8 (Page 30–31): Profit and Loss

I. A) Find profit or loss:

S.noCost PriceSelling PriceProfit/LossHow much
1₹2,600₹2,400Loss₹200
2₹5,000₹6,000Profit₹1,000
3₹6,200₹5,000Loss₹1,200
4₹8,000₹8,999Profit₹999

I. B) Fill the blanks:

S.noCost PriceSelling PriceProfit/LossHow much
1₹1,200₹1,000loss200
2₹2,500₹3,500profit1000
3₹8,500₹10,000profit1500
4₹6,800₹6,300loss500

II. Shankar's smartphone: CP = ₹18,700, SP = ₹15,500. Since SP < CP, he made a loss of ₹3,200

III. Dhanu's investment = Amount received − Profit = 58,524 − 7,524 = ₹51,000

IV. SP = 5,450, Profit = 750, so Cost price = Selling price − Profit → Option A) Cost price = 5,450 − 750

Self Assessment (Page 32–33)

I. 4,986 + 3,470 − 5,467 → Add: 4,986+3,470=8,456; Subtract: 8,456−5,467 = 2,989

II. a) Stamps Syed had in the beginning = 100 − 25 = 75 stamps

II. b) Stamps Vinay has left = 96 − 25 = 71 stamps

III. Total weight of sweets = 2,500 + 1,500 + 750 + 500 = 5,250 g (5.25 kg)

IV. Books in library now = 12,450 + 3,875 − 2,690 = 16,325 − 2,690 = 13,635 books

V. Total cost = ₹800 (tomatoes) + ₹150 (transport) = ₹950. Selling price = ₹1,000. Actual profit = 1,000 − 950 = ₹50, not ₹200 as stated. His statement is incorrect — he forgot to add the ₹150 transport cost to his cost price while calculating profit.

VI. Sample word problem: "Meena bought 1 notebook (₹40), 1 pen (₹30) and 1 school bag (₹300). How much did she spend in total, and how much change would she get from ₹500?"
Total spent = 40 + 30 + 300 = ₹370; Change from ₹500 = 500 − 370 = ₹130 (Answers may vary as this is a creative question.)

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