AP 5th Maths 3rd Unit Multiplication and Division Workbook Answers, Solutions. Class 5 Maths Workbook – Unit 3: Multiplication and Division (Worksheets 1 to 12 & Self Assessment) – Solved Answers.
This post gives complete, step-by-step solved answers for Class 5 Maths Workbook Unit 3 – Multiplication and Division, covering all worksheets from Worksheet-1 to Worksheet-12 and the Self Assessment pages. Topics include recall of multiplication, multiplication process for 4-digit numbers, word problems on multiplication and division, division estimation, unitary method, and the relationship between multiplication and division. Every word problem is explained with clear "Given → Formula → Answer" style working so that children can easily follow the steps. These AP SCERT Class 5 Maths Workbook solutions are ideal for CBSE/AP State Board students, parents helping with homework, and teachers preparing answer keys. Keywords: Class 5 Maths Workbook answers, Multiplication and Division Unit 3, AP SCERT 5th class maths solutions, worksheet answers with word problems, unitary method examples for kids.
AP 5th Maths 3rd Unit Multiplication and Division Workbook Answers, Solutions
Worksheet - 1 | Sub Topic: Recall Multiplication
I) Do the following Multiplications.
a) 214 × 88 = 18832
b) 750 × 120 = 90000
II) Do the following Multiplications in expanded form.
a) 46 × 8
| × | 40 | 6 |
| 8 | 320 | 48 |
Total = 320 + 48 = 368 (46 × 8 = 368)
b) 86 × 12
| × | 80 | 6 |
| 10 | 800 | 60 |
| 2 | 160 | 12 |
Total = 800+60+160+12 = 1032 (86 × 12 = 1032)
III) The shapes stand for numbers between 1 and 24. Find the hidden numbers.
Working out the shape values step by step: Box = 3, Circle = 4, so Box × Circle = 3 × 4 = 12 (Triangle).
a) 3 × 4 = 12
b) Box × Box = 3 × 3 = 9
c) Parallelogram(2) × Diamond(6) = 12
d) Diamond(6) × Green Pentagon(4) = 24
e) Parallelogram(2) × Circle(4) = 8
f) Teardrop(8) × Box(3) = Parallelogram(2) × Triangle(12) → 24 = 24 (verified)
IV) 300 × 3 is equivalent to: ( C )
300 × 3 = 900; Check: C) 10 × 90 = 900 ✔ Answer: C) 10 × 90
Worksheet - 2 | Sub Topic: Multiplication Process
I) Complete the following Multiplications.
a) 3301 × 3 = 9903
b) 4650 × 90 = 418500
II) a) Fill the box with suitable number:
403 × 2 = 806 (403 × 2 = 806)
b) Match the following:
ii) 450 × 2 = 900 → A
iii) 690 × 1 = 690 → B
iv) 330 × 5 = 1650 → C
III) Madhu drinks 8 glasses of water every day.
a) How many glasses of water does he drink in one week?
Number of days in 1 week = 7
Glasses of water he drinks in 1 week = 8 × 7
= 56 glasses
b) How many glasses of water does he drink in November month?
Number of days in November month = 30
Glasses of water he drinks in November = 8 × 30
= 240 glasses
c) How many glasses of water does he drink in one year?
Number of days in 1 year = 365
Glasses of water he drinks in 1 year = 8 × 365
= 2920 glasses
IV) The cost of a chair is ₹550 and the cost of a table is ₹950. If Nagamani purchases 3 chairs and 3 tables, how much amount does she have to pay?
Cost of 1 table = ₹950
Number of chairs purchased = 3, Number of tables purchased = 3
Cost of 3 chairs = 3 × 550 = ₹1650
Cost of 3 tables = 3 × 950 = ₹2850
Total amount to be paid = 1650 + 2850
= ₹4500
Worksheet - 3 | Sub Topic: Multiplication Process
I) Do the following.
a) 7256 × 4 = 29024
b) 4689 × 16 = 75024
II) Observe the multiplication, identify and circle the mistake. Then do it correctly.
a) 8657 × 8 (shown wrongly as 68856)
Correct: 8657 × 8 = 69256
b) 9243 × 12 (18486 + 92430 wrongly added as 8605)
Correct: 18486 + 92430 = 110916
III) Naveen's heart beats 72 times in one minute.
a) How many times does it beat in an hour?
Number of minutes in 1 hour = 60
Heart beats in 1 hour = 72 × 60
= 4320 times
b) How many times does it beat in one day?
Number of hours in 1 day = 24
Heart beats in 1 day = 4320 × 24
= 103680 times
c) How many times does it beat in one week?
Number of days in 1 week = 7
Heart beats in 1 week = 103680 × 7
= 725760 times
IV) A juice maker uses 2 apples to make a glass of juice. How many apples are required to make 364 glasses of juice?
Number of glasses of juice to be made = 364
Apples required for 364 glasses = 2 × 364
= 728 apples
Worksheet - 4 | Sub Topic: Making Word Problems on Multiplication and Division
I) Read the questions, underline the multiplication questions, then rewrite in the place provided.
1) a) 396 ÷ 18 b) 4392 × 27 c) 6590 + 598 d) 7596 − 666
Multiplication question here is (b), since it uses the × sign.
2) a) 95,732 is how much greater than 82,365? — this is subtraction.
b) Find the sum of 3657 and 4444 — this is addition.
c) There are 180 apples in a box. How many apples will there be in 7 full boxes? — this is multiplication.
d) 40 charts cost ₹320, cost of 1 chart? — this is division.
Rewritten multiplication statements with answers:
Multiplied by = 27
4392 × 27 = 118584
Number of full boxes = 7
Total apples in 7 boxes = 180 × 7
= 1260 apples
II) Observe the picture (hotel, dosa), use the hints to create a word problem on multiplication. (Hints: hotel, Raju, plate 30, per day, Dosa)
Given: Number of Dosa plates sold in 1 day = 30
Number of days = 12
Number of plates sold in 12 days = 30 × 12
= 360 plates
Worksheet - 5 | Sub Topic: Making Word Problems on Multiplication
b) Observe the picture (general store), create a word problem on multiplication. (Hints: General store, Malik, Rice bag ₹4500)
Given: Cost of 1 rice bag = ₹4500
Number of rice bags sold = 6
Total money earned = 4500 × 6
= ₹27,000
III) Use 1261 × 9 and create a word problem on multiplication, then solve it.
Given: Pens packed in 1 carton = 1261
Number of cartons = 9
Total pens in 9 cartons = 1261 × 9
= 11349 pens
IV) A.P government has decided to plant trees along a 112 km road. As 30 trees per half kilometre, how many trees can be planted along 112 km?
Total length of road = 112 km
Number of half-km stretches in 112 km = 112 ÷ 0.5 = 224
Total trees planted = 224 × 30
= 6720 trees
Worksheet - 6 | Sub Topic: Multiplication on Word Problems
I) Fill in the blanks using multiplication properties.
a) 45 × 189 = 189 × 45 (Commutative property)
b) 657 × 468 = 468 × 657 (Commutative property)
c) 369 × 1 = 369 (Multiplicative identity)
d) 25607 × 0 = 0 (Zero property)
II) Do the following multiplication within one minute.
a) 365 × 100 = 36500 b) 4510 × 10 = 45100
c) 961 × 1 = 961 d) 2810 × 0 = 0
e) 281 × 565 = 565 × 281 f) 628 × 1000 = 628000
III) Chakri is a tailor. He charges ₹850 for stitching a pair. During festival season he stitched 75 pairs. Find the total amount he earned.
a) Charge for stitching a pair = ₹850
b) Pairs stitched during festive season = 75
c) Operation used = Multiplication
IV) Chakri is a tailor. He charges ₹850 for stitching a pair. During festival season he stitched 75 pairs. Find the total amount he earned. What is the problem about?
No. of pairs stitched = 75
Stitching charge for 75 pairs = 850 × 75
= ₹63,750
The problem is about finding the total earnings of a tailor who is paid a fixed rate per pair for a given number of pairs stitched, using multiplication.
V) Gaja is a tailor. He charges ₹750 for stitching a pair. During festival season he stitched 124 pairs. Find the total amount he earned.
No. of pairs stitched = 124
Stitching charge for 124 pairs = 750 × 124
= ₹93,000
Worksheet - 8 | Sub Topic: Word Problems on Division
I) A cement factory produces 4350 bags of cement in a month (30 days). How many bags does it produce in one day?
a) Information given: 4350 bags produced in 30 days
b) What is to be found: Number of bags produced in one day
c) Mathematical operation to be used: Division
II) Same problem, step by step:
a) Bags of cement produced in a month = 4350
b) Days in a month = 30
c) Bags of cement produced in a day = 4350 ÷ 30 = 145
III) sol:
Number of days in a month = 30
Number of cement bags produced by the factory in a day = 4350 ÷ 30
= 145 bags
IV) A steel factory makes 9990 steel boxes in a month (30 days). How many steel boxes does it make in one day?
Number of days in a month = 30
Number of steel boxes made by the factory in a day = 9990 ÷ 30
= 333 boxes
Worksheet - 9 | Sub Topic: Unitary Method
I) a. Complete the table (pen packets: Blue ₹50/10 pens, Red ₹60/10 pens, Black ₹70/10 pens, Green ₹100/10 pens):
| Kumar | Number of pens purchased | Amount to be paid |
| Blue | 4 | ₹20 (₹5 per pen) |
| Red | 2 | ₹12 (₹6 per pen) |
| Black | 5 | ₹35 (₹7 per pen) |
| Green | 1 | ₹10 (₹10 per pen) |
b) The cost of 3 dozen eggs is ₹156, what is the cost of 7 dozen eggs? (1 Dozen = 12)
Cost of 1 dozen eggs = 156 ÷ 3 = ₹52
Cost of 7 dozen eggs = 52 × 7
= ₹364
Worksheet - 10 | Sub Topic: Unitary Method
II) The cost of a 100 kg rice bag is ₹4800, what is the cost of a 25 kg rice bag?
Cost of 1 kg rice = 4800 ÷ 100 = ₹48
Cost of 25 kg rice = 48 × 25
= ₹1200
III) The cost of 45 metres of electric wire is ₹3540, how much does it cost to buy 24 metres of the same wire?
Cost of 1 m of wire = 3540 ÷ 45
Cost of 24 m of wire = (3540 ÷ 45) × 24
= ₹1888
IV) Write four daily life situations to use the unitary method.
Sample answers:
1) Finding the cost of 1 pencil when the price of a box of pencils is known.
2) Finding how much petrol is needed for 1 km when the mileage for a full tank is known.
3) Finding the cost of 1 kg of vegetables when the price of a sack is known.
4) Finding the wage for 1 day of work when the total wage for several days is known.
IV) (second) A family requires ₹6400 for 8 days, how much money does the family require for 6 days?
Money required for 1 day = 6400 ÷ 8 = ₹800
Money required for 6 days = 800 × 6
= ₹4800
Worksheet - 11 | Sub Topic: Division Estimation
I) Estimate the quotient, verify by doing division.
| Question | Estimation | Division | Correct/Wrong |
| 463 ÷ 12 | 460 ÷ 10 ≈ 46 | 38, remainder 7 | Correct (12×38+7=463) |
| 642 ÷ 18 | 640 ÷ 20 ≈ 32 | 35, remainder 12 | Correct (18×35+12=642) |
II) Estimate the result and verify by doing the division.
a) 2410 ÷ 5 → estimate 2400 ÷ 5 = 480; exact = 482 (5×482=2410)
b) 908 ÷ 21 → estimate 900 ÷ 20 = 45; exact = 43, remainder 5 (21×43+5=908)
III) A farmer harvested 6,980 guavas. He arranges them in trays of 38 guavas, estimate how many trays he will need.
Guavas kept in each tray = 38 (round to 40)
Estimated number of trays needed = 7000 ÷ 40
= 175 trays (approx.)
IV) A group of students collected 9,080 plastic bottles for recycling. They will pack them in bags of 113 bottles each, how many bags will they need? ( A )
Bottles packed in each bag = 113 (round to 100)
Estimated number of bags needed = 9000 ÷ 100
= 90 bags
Answer: A) 90
Worksheet - 12 | Sub Topic: Division
I) Match the Division form with the Multiplication form.
ii) 7800 ÷ 12 = 650 → a) 650 × 12 = 7800
iii) 5555 ÷ 11 = 505 → d) 505 × 11 = 5555
iv) 9990 ÷ 9 = 1110 → c) 1110 × 9 = 9990
II) Write two multiplication and two division statements.
| Number Set | Multiplication Statement | Division Statement |
| 360, 12, 30 | 12 × 30 = 360 and 30 × 12 = 360 | 360 ÷ 12 = 30 and 360 ÷ 30 = 12 |
| 400, 10, 40 | 10 × 40 = 400 and 40 × 10 = 400 | 400 ÷ 10 = 40 and 400 ÷ 40 = 10 |
III) A number multiplied by 36 gives the product 1,080. Make division to find the number. Write both multiplication and division sentences.
The number = 1080 ÷ 36
= 30
Division sentence: 1080 ÷ 36 = 30
Multiplication sentence (to verify): 36 × 30 = 1080
Self Assessment
I) Do the following Multiplication and Division.
a) 809 × 35 = 28315
b) 2226 ÷ 22 = 101, remainder 4
II) Observe, identify the mistake and correct it.
a) 5234 × 65 (shown wrongly as 26170 + 31404 = 57574)
Mistake: 5234 × 60 should be 314040 (written as 31404, missing a zero).
Correct: 26170 + 314040 = 340210
b) 4028 ÷ 4 (shown wrongly as quotient 107)
Correct quotient: 1007, remainder 0 (4 × 1007 = 4028)
III) One day Raghu sold 425 packets of groundnuts. If each packet costs ₹10, then find the total amount he earned on that day.
Number of packets sold = 425
Total amount earned = 425 × 10
= ₹4250
IV) The prices of two items are: Fan ₹2050, Table ₹2125. If Suma decides to purchase 4 fans and 3 tables, how much amount does she have to pay in total?
Number of fans purchased = 4, Number of tables purchased = 3
Cost of 4 fans = 4 × 2050 = ₹8200
Cost of 3 tables = 3 × 2125 = ₹6375
Total amount to be paid = 8200 + 6375
= ₹14,575
V) A student states if we multiply a number by 10 and then divide it by 5 the result will be double the number.
a) Is the student given correct statement? Yes, the statement is correct.
Multiply by 10 = 6 × 10 = 60
Divide by 5 = 60 ÷ 5 = 12
Double of the number 6 = 2 × 6 = 12
Since 12 = 12, the statement is verified as correct.
VI) Use 809 × 25 and create a word problem on multiplication.
Given: Notebooks in 1 box = 809
Number of boxes bought = 25
Total notebooks bought = 809 × 25
= 20,225 notebooks
