Class 5 Maths Textbook (Maths Magic) – Unit 3: Multiplication and Division – Complete Solved Answers.
This post provides complete, step-by-step solved answers for Class 5 Maths Textbook Unit 3 – Multiplication and Division (AP SCERT Maths Magic), including all "Do these" activities, "Think & Discuss", "Let's Estimate", the Activity grid, the main Unit Exercise, and the "Improve Your Learning" section. It covers multiplying 4-digit numbers by 1, 2 and 3-digit numbers, framing word problems, estimating products and quotients, dividing 4-digit numbers, the unitary method, and the relationship between multiplication and division. Every word problem is explained with a clear "Given → Step → Answer" style working so children can easily follow along. These AP SCERT Class 5 Maths solutions are ideal for students, parents, and teachers preparing answer keys. Keywords: Class 5 Maths Textbook answers, Multiplication and Division Unit 3 solutions, AP SCERT 5th class Maths Magic answers, unitary method for kids, division estimation examples.
AP 5th Maths 3rd Unit Multiplication and Division Textbook Answers, Solutions
Page 71-72: Expenditure Table – Multiplication
How much amount was spent to purchase the material?
| Item | Cost per unit (₹) | Number of units | Total amount (₹) |
| Sand | 3000 | 3 | 9000 |
| Cement bricks | 16 | 500 | 8000 |
| Iron | 80 | 122 | 9760 |
| Cement | 435 | 50 | 21750 |
| Gravel | 4000 | 2 | 8000 |
= ₹56,510
Page 72-74: Helper's Wage & Which Method Did You Like?
Which of the above three methods did you like? Why?
Open-ended answer: All three methods (Sai's, Harshitha's, and Devi's) give the same correct answer, ₹29,450. Devi's method of splitting 31 as (1 + 30) and multiplying separately is easy and quick because it uses place value and avoids mistakes.
Page 76: Do these (Multiplication of 4-digit numbers)
1) Do the following.
a) 245 × 2 = 490 b) 2835 × 3 = 8505
c) 3746 × 5 = 18730 d) 4539 × 6 = 27234
2) A factory manufactures 4950 cars in a month. How many cars will the factory produce in a year?
Number of months in a year = 12
Number of cars produced in a year = 4950 × 12
= 59,400 cars
Page 80: Multiplication with 10, 100, 1000 – Complete the Table
| 10 × | 20 × | 100 × | 1000 × |
| 10×1=10 | 20×1=20 | 100×1=100 | 1000×1=1000 |
| 10×2=20 | 20×2=40 | 100×2=200 | 1000×2=2000 |
| 10×3=30 | 20×3=60 | 100×3=300 | 1000×3=3000 |
| 10×4=40 | 20×4=80 | 100×4=400 | 1000×4=4000 |
| 10×5=50 | 20×5=100 | 100×5=500 | 1000×5=5000 |
| 10×6=60 | 20×6=120 | 100×6=600 | 1000×6=6000 |
| 10×7=70 | 20×7=140 | 100×7=700 | 1000×7=7000 |
| 10×8=80 | 20×8=160 | 100×8=800 | 1000×8=8000 |
| 10×9=90 | 20×9=180 | 100×9=900 | 1000×9=9000 |
| 10×10=100 | 20×10=200 | 100×10=1000 | 1000×10=10000 |
Observe the image (sarees shop) and prepare a word problem. (Hints: Hema, sarees shop, ₹650 × 5)
Given: Cost of 1 saree = ₹650
Number of sarees bought = 5
Total money paid = 650 × 5
= ₹3250
Page 82: Do these
1) Do the multiplications and prepare a suitable word problem.
a) 3628 × 9 = 32652 b) 4256 × 23 = 97888
2) Amar sells a cup of tea for ₹6. If 1100 cups of tea were sold in a day, how much amount did he earn?
Number of cups sold in a day = 1100
Total amount earned = 6 × 1100
= ₹6600
3) Carpenter Johnson made 9 cots and sold each cot for ₹8,500. How much amount did he earn?
Number of cots made and sold = 9
Total amount earned = 9 × 8500
= ₹76,500
Page 82-84: Think & Discuss – Butter Packets Pattern
a) 2 × 3 = 6 3 × 2 = 6
b) 5 × 8 = 40 8 × 5 = 40
c) 6 × 13 = 78 13 × 6 = 78
d) 10 × 5 = 50 5 × 10 = 50
e) 8 × 20 = 160 20 × 8 = 160
f) 12 × 9 = 108 9 × 12 = 108
What pattern did you notice? The product of two numbers remains the same even when their order is changed. This is called the commutative property of multiplication.
Page 84: Multiplication with 1
1) 89 × 1 = 89 2) 261 × 1 = 261 3) 4589 × 1 = 4589
What do you observe? The product of any number and 1 is the number itself. 1 is called the multiplicative identity.
Page 86: Multiplication with '0'
1) 56 × 0 = 0 2) 258 × 0 = 0 3) 0 × 953 = 0
What do you observe? The product of any number and zero is always zero. This is known as the zero property of multiplication.
Do these:
1) Find the products: 46 × 23 = 1058 and 23 × 46 = 1058
2) a) 23 × 1 = 23 b) 342 × 1 = 342 c) 999 × 1 = 999
d) 53 × 0 = 0 e) 259 × 0 = 0 f) 5817 × 0 = 0
Page 86-87: Let us Estimate – Do these
Estimate the products of these multiplications (round to nearest tens then multiply):
1) 59 × 19 → 60 × 20 = 1200
2) 99 × 56 → 100 × 60 = 6000
3) 189 × 33 → 190 × 30 = 5700
Page 88-92: Division – Do these
1) Do the following divisions. Write dividend, divisor, quotient and remainder. Verify using the division relation.
a) 9786 ÷ 6: Dividend=9786, Divisor=6, Quotient=1631, Remainder=0.
Verify: Dividend = (Divisor × Quotient) + Remainder = (6 × 1631) + 0 = 9786 ✔
b) 5682 ÷ 9: Dividend=5682, Divisor=9, Quotient=631, Remainder=3.
Verify: (9 × 631) + 3 = 5679 + 3 = 5682 ✔
2) Raju bought 120 blankets with ₹6000 to distribute to orphans. What is the cost of each blanket?
Number of blankets bought = 120
Cost of each blanket = 6000 ÷ 120
= ₹50
3) Do the following and write the quotient and remainder in each case. What did you observe?
a) 53427 ÷ 10 → Quotient=5342, Remainder=7
b) 53427 ÷ 100 → Quotient=534, Remainder=27
c) 53427 ÷ 1000 → Quotient=53, Remainder=427
d) 53427 ÷ 10000 → Quotient=5, Remainder=3427
Observation: When we divide a number by 10, 100, 1000 or 10000, the quotient is formed by removing that many digits from the right end of the number, and the removed digits form the remainder.
Page 94: Unitary Method – Do these
1) If 8 pots cost ₹800, what would be the cost of 5 pots?
Cost of 1 pot = 800 ÷ 8 = ₹100
Cost of 5 pots = 100 × 5
= ₹500
2) If 5 kg tomatoes cost ₹125, what would be the cost of 2 kg tomatoes?
Cost of 1 kg tomatoes = 125 ÷ 5 = ₹25
Cost of 2 kg tomatoes = 25 × 2
= ₹50
3) A publisher printed 3,875 books in the month of July. If the publisher makes the same number of books in every month, how many books can be printed in a leap year?
Number of months in a year = 12
Total books printed in a year = 3875 × 12
= 46,500 books
(Note: A leap year still has 12 months, so the number of months used for multiplication does not change with a leap year.)
Page 96: Activity – Solve and Colour
| Problem | Answer |
| 21 × 16 | 336 |
| 15 × 7 | 105 |
| 181 × 5 | 905 |
| 288 ÷ 4 | 72 |
| 576 ÷ 12 | 48 |
| 78 ÷ 3 | 26 |
These answers (336, 105, 905, 72, 48, 26) should be coloured/circled in the number grid.
Page 96: Let's Estimate
Whose estimation is correct?
Number of labourers = 4
Estimated amount each labourer gets = 4000 ÷ 4
= ₹1000
Bhima said ₹1500, Ahmed said ₹1000, Saradha said ₹700, Laxmi said ₹800.
Name of the person who estimated correctly: Ahmed
Page 98: Do these – Estimating Quotients
1) Estimate the result:
a) 309 ÷ 11 → 310 ÷ 10 = ≈ 31
b) 497 ÷ 23 → 500 ÷ 20 = ≈ 25
c) 891 ÷ 32 → 890 ÷ 30 = ≈ 30
2) Johnny bought 5 packets of buns each containing 20, to distribute on his birthday. If he distributed the buns equally to 48 patients, how many buns will each patient get approximately?
Total buns = 5 × 20 = 100
Number of patients = 48 (round to 50)
Estimated buns each patient gets = 100 ÷ 50
= 2 buns each (approx.)
Page 98: Relation between Multiplication and Division – Fill in the Blanks
| Multiplication | Division fact-1 | Division fact-2 |
| 10 × 2 = 20 | 20 ÷ 2 = 10 | 20 ÷ 10 = 2 |
| 23 × 4 = 92 | 92 ÷ 4 = 23 | 92 ÷ 23 = 4 |
| 52 × 12 = 624 | 624 ÷ 12 = 52 | 624 ÷ 52 = 12 |
| 500 × 4 = 2000 | 2000 ÷ 4 = 500 | 2000 ÷ 500 = 4 |
| 36 × 18 = 648 | 648 ÷ 18 = 36 | 648 ÷ 36 = 18 |
| 527 × 15 = 7905 | 7905 ÷ 15 = 527 | 7905 ÷ 527 = 15 |
Page 100: Write Multiplication Forms for the Divisions
| Division form | Multiplication form |
| 54 ÷ 6 = 9 | 9 × 6 = 54 |
| 168 ÷ 12 = 14 | 14 × 12 = 168 |
| 792 ÷ 22 = 36 | 36 × 22 = 792 |
| 200 ÷ 5 = 40 | 40 × 5 = 200 |
| 1265 ÷ 23 = 55 | 55 × 23 = 1265 |
| 2262 ÷ 39 = 58 | 58 × 39 = 2262 |
EXERCISE (Page 100-102)
1. The cost of a bicycle is ₹4,950. The cost of a motor cycle is 13 times the bicycle's cost. What is the cost of the motor cycle?
Cost of Motor Cycle = 13 times of Bicycle's Cost
= 13 × 4950
= ₹64,350
2. A carton can hold 36 mangoes. How many such cartons are required if there are 4,320 mangoes in all?
Mangoes held by 1 carton = 36
Number of cartons required = 4320 ÷ 36
= 120 cartons
3. The owner of a cell phone shop bought 8 cell phones at the same price and gave ₹9,800 to the wholesaler. The wholesaler returned him ₹200. What is the cost of each cell phone?
Amount returned by wholesaler = ₹200
Actual amount paid for 8 phones = 9800 − 200 = ₹9600
Number of cell phones bought = 8
Cost of each cell phone = 9600 ÷ 8
= ₹1200
4. A fisher man wants to sell 8 kg of fish for ₹1,600. But Ramu wants to buy 5 kg only. Find the cost of 5 kg fish.
Cost of 1 kg fish = 1600 ÷ 8 = ₹200
Cost of 5 kg fish = 200 × 5
= ₹1000
5. Harsha painted pictures and sold them in an art gallery. He charged ₹2,567 for a big painting and ₹465 for a small painting. He sold 6 large paintings and 3 small paintings. How much amount did he earn?
Number of big paintings sold = 6, Number of small paintings sold = 3
Amount earned from big paintings = 6 × 2567 = ₹15,402
Amount earned from small paintings = 3 × 465 = ₹1,395
Total amount earned = 15402 + 1395
= ₹16,797
6. The cost price of 3kg apples is ₹360, then find the cost of apples for 2 kg.
Cost of 1 kg apples = 360 ÷ 3 = ₹120
Cost of 2 kg apples = 120 × 2
= ₹240
7. Swetha multiplied the number of eggs in her basket by 312. The answer was a number between 4000 and 4300. What could be the number of eggs in her basket? ( D )
Check option D) 13 × 312 = 4056 → lies between 4000 and 4300 ✔
Check A) 10×312=3120 ✘, B) 11×312=3432 ✘, C) 20×312=6240 ✘
Answer: D) 13
8. A shop keeper had 297 story books. He wanted to pack them equally into 8 boxes. How many story books would be left unpacked? ( A )
Number of boxes = 8
297 ÷ 8 = 37, remainder 1
Answer: A) 1
9. Do the following problems within 5 minutes.
| Multiply 300 × 5 = 1500 |
Identify spelling mistake: Multiplication, |
If 8 books cost ₹800, cost of 5 books? 1 book=₹100; 5 books=₹500 |
200 ÷ 5 = 40; multiplication form: 40 × 5 = 200 |
390 ÷ 13 = 30 |
| 426 × 24 = 24 × 426 | Estimate 13 × 21: 10 × 20 = 200 |
3650 × 0 = 0 | Complete division relation: Dividend = (Divisor × Quotient) + Remainder |
Colour a star for each problem solved correctly within 5 minutes: ★★★★★★★★★ (all 9 stars for all correct answers above).
Fun with Maths (Page 102)
Pattern 1 – Observe and continue:
1 × 1 = 1
11 × 11 = 121
111 × 111 = 12321
1111 × 1111 = 1234321
11111 × 11111 = 123454321
Pattern 2 – Observe and continue:
1 × 9 = 9
12 × 9 = 108
123 × 9 = 1107
1234 × 9 = 11106
12345 × 9 = 111105
Improve Your Learning (Page 104)
1. In 5436 ÷ 7, Quotient = 776, Remainder = 4 (7 × 776 + 4 = 5436)
2. 345 books were bought for the school library. These books have to be packed into boxes that hold 15 books each. Which of the following could be used to find the number of boxes needed? ( d )
Number of boxes needed = 345 ÷ 15
= 23 boxes
3. A school group is heading to the zoo on six buses. The first five buses, each accommodating 40 students, are full. The last bus has 5 empty seats. In total, how many students are going to the zoo?
Bus capacity = 40, Empty seats in the last bus = 5
Students in 5 full buses = 5 × 40 = 200
Students in the last bus = 40 − 5 = 35
Total students going to the zoo = 200 + 35
= 235 students
4. A division problem solved correctly is shown below. Which digit should go in the empty box?
6 ) 636
Since 6 × 106 = 636, the missing digit is 3.
5. Shop 'A' sells a pack of 5 pens for ₹100. Shop 'B' sells a pack of 8 pens for ₹152. The cost of a pen is low in price in shop 'A', compare to shop 'B'. Write "Yes" or "No" and provide a mathematical reason to support your answer.
Cost of 1 pen in Shop A = 100 ÷ 5 = ₹20
Cost of 1 pen in Shop B = 152 ÷ 8 = ₹19
Since ₹20 (Shop A) is greater than ₹19 (Shop B):
Answer: No. The pen is actually cheaper in Shop B (₹19), not Shop A (₹20).
6. Cost of 1 meal is ₹110. If you have ₹1000 how many meal can you arrange? To arrange 1 more meal how much money do you need?
Money available = ₹1000
Number of meals arranged = 1000 ÷ 110 = 9, remainder ₹10
Money left over after 9 meals = ₹10
Money needed for 1 more meal = 110 − 10
= ₹100 more needed
So, he can arrange 9 meals, and needs ₹100 more to arrange 1 additional meal.
7. A pension holder gets a pension of ₹9,950 per month. How much pension will he get in one year?
Number of months in a year = 12
Pension in one year = 9950 × 12
= ₹1,19,400
8. Sara wants to buy a certain kind of toy. Each toy costs ₹1,000. If she has ₹50,000, how many toys can she buy?
Money Sara has = ₹50,000
Number of toys she can buy = 50000 ÷ 1000
= 50 toys
9. A shopkeeper had 4297 storybooks. He wanted to pack them equally into 18 boxes. How many storybooks would be left unpacked?
Number of boxes = 18
4297 ÷ 18 = 238, remainder 13
So, 13 storybooks would be left unpacked.
10. 28 laddoos weigh 1 kg. How many laddoos weigh 12 kgs. If 16 laddoos can be packed in one box, how many boxes are needed to pack all these laddoos?
Total weight = 12 kg
Number of laddoos in 12 kg = 28 × 12
= 336 laddoos
Laddoos packed in 1 box = 16
Number of boxes needed = 336 ÷ 16
= 21 boxes
